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Question

Solve the equation
x4+1125=134x2

A
{55,3,3,55}
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B
{3,55}
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C
{9,125}
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D
{125,9,9,125}
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Solution

The correct option is A {55,3,3,55}
x4134x2+1125=0
Let x2=t
So, it will reduce to t2134t+1125=0.
t2125t9t+1125=0t(t125)9(t125)=0(t9)(t125)=0t=9,125x2=tx2=9orx2=125x=3,3orx=55,55

The values of x are 3,3,55,55.

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