Solve the equation $y = x^{2} - 2 x - 3$ .

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Solution

Let us draw the graph of $y = x^{2} - 2 x - 3$

Now consider the following table by assigning integer values from –3 to 4 in and finding the corresponding values of $y = x^{2} - 2 x - 3$

$\begin{matrix} x & - 3 & - 2 & - 1 & 0 & 1 & 2 & 3 & 4 x^{2} & 9 & 4 & 1 & 0 & 1 & 4 & 9 & 16 - 2 x & 6 & 4 & 2 & 0 & - 2 & - 4 & - 6 & - 8 - 3 & - 3 & - 3 & - 3 & - 3 & - 3 & - 3 & - 3 & - 3 y & 12 & 5 & 0 & - 3 & - 4 & - 3 & 0 & 5 \end{matrix}$

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Similar questions

x^{2} - 2 x - 3 = 0

(1) Draw the graph of y = x² and y = 2x + 3 and hence solve the equation x² − 2x − 3 = 0.

(2) Draw the graph of y = 2x²and y = 3 − x and hence solve the equation 2x² + x − 3 = 0.

(3) Draw the graph of y = 2x² and y = 3 + x and hence solve the equation 2x² − x − 3 = 0.

\sqrt{x^{2} + 2 x + 1} - \sqrt{x^{2} - 4 x + 4} = 3

x^{2} - 2 x + \frac{3}{2} = 0

Draw the graph $y = x^{2} - 9$ and hence solve the equation $x^{2} - 2 x - 8 = 0$