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Question

Solve the equations:

(10) 3b + 5 = 5 (b + 1)

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Solution

3b + 5 = 5 (b + 1)
3b + 5 = 5b + 5
Subtracting 5b from both sides, we obtain:
3b + 5 – 5b = 5b + 5 – 5b
–2b + 5 = 5
Subtracting 5 from both sides, we obtain:
–2b + 5 – 5 = 5 – 5
–2b = 0
Dividing both sides by – 2, we obtain:
-2b-2=0-2b=0

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