Question

Solve the equations:

(12) 5 (8 – y) = 3y + 13

Answer 1

5 (8 – y) = 3y + 13
$\Rightarrow$40 – 5y = 3y + 13
Subtracting 3y from both sides, we obtain:
40 – 5y – 3y = 3y + 13 – 3y
$\Rightarrow$40 – 8y = 13
Subtracting 40 from both sides, we obtain:
40 – 8y – 40 = 13 – 40
$\Rightarrow$– 8y = –27
Dividing both sides by – 8, we obtain:
$$\begin{gathered} \frac{-8y}{-8}=\frac{-27}{-8} \\ \Rightarrow y=\frac{27}{8} \end{gathered}$$