Question

Solve the equations:

$2x+4y=3$;
$12y+6x=6$

• A. $x=1;y=2$
• B. $x=-1;y=-2$
• C. $x=1;y=-2$
• D. None of above

Answer 1

The correct option is D None of above

The given pair of linear equation is-

$2x+4y-3=0$ and $6x+12y-6=0$

here,$a_1=2,b_1=4,c_1=-3$

and $a_2=6,b_2=12,c_2=-6$

$\therefore \frac{a_1}{a_2}=\frac{2}{6}=\frac{1}{3}$

$\frac{b_1}{b_2}=\frac{4}{12}=\frac{1}{3}$

$\frac{c_1}{c_2}=\frac{-3}{-6}=\frac{1}{2}$

Hence$\frac{a_1}{a_2}=\frac{b_1}{b_2}\ne \frac{c_1}{c_2}$

Then the given pair of linear equation has no solution.