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Question

Solve the equations
3(sec2θ+tan2θ)=5.

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Solution

Consider the given equation.

3(sec2θ+tan2θ)=5

sec2θ+tan2θ=53

We know that

sec2θ=1+tan2θ

Therefore,

1+tan2θ+tan2θ=53

2tan2θ=531

2tan2θ=23

tan2θ=13

tanθ=13

tanθ=tanπ6

θ=nπ+π6

Hence, this is the answer.


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