Solve the equations 3x–y=5, x+3y=5
2, 1
Given equations
3x – y = 5...........(i)
x + 3y = 5........(ii)
Since the coefficient of x in (i) is equal to coefficient of y in (ii) and the coefficient of y in (i) is equal to coefficient of x in (ii)
Adding (i) and (ii)
4x + 2y = 10 ⇒ 2x + y = 5......(iii)
Subtracting (i) and (ii) we get
2x - 4y = 0 ⇒ x - 2y = 0 or x = 2y........(iv)
Substituting (iv) in (iii) we get
5y = 5 or y = 1
⇒ x = 2 (from iv)