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Question

Solve the equations using elimination method:
5a6b=2 and 6a5b=9

A
(4, -3)
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B
(-4, 3)
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C
(4, 3)
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D
(-4, -3)
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Solution

The correct option is C (4, 3)
5a6b=2 ----- (1)
6a5b=9 ----- (2)
Multiply equation (1) by 6 and equation (2) by 5, and then subtract the equation (3) and (4)
30a36b=12 ----- (3)
30a25b=45 ----- (4)
(-) (+) (-)
______________
11b=33
b=3311=3
Put the value of b in equation (1), we get
5a6b=2
5a6(3)=2
5a=2+18
a=205=4
Therefore the solution is (4, 3)

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