Question

Solve the equations using elimination method:
$a-2b=2$ and $3a-2b=6$

• A. (2, -1)
• B. (2, 1)
• C. (2, 0)
• D. (-2, 1)

Answer 1

The correct option is C (2, 0)

Subtract equation 1 and 2,
$a-2b=2$ ----- (1)
$3a-2b=6$ ----- (2)
(-) (+) (-)
____________
$-2a=-4$
$a=\frac{-4}{-2}=2$
Put the value of a in equation (1), we geta
$a-2b=2$
$2-2b=2$
$-2b=2-2$
$-2b=0$
$b=\frac{0}{-2}=0$
Therefore the solution is (2, 0)