x−y+1=0 ------- (3)
Put x=2,y=3 in equation (3)
2−3+1=0
−1+1=0
0=0
Again put x=4,y=5 in equation (3)
4−5+1=0
−1+1=0
0=0
Now plotting (2,3),(4,5) and joining them, we get a straight line.
From equation (2) assume the value of x and y to satisfy the equation to zero.
2y+3x−12=0 ----- (4)
Put x=2,y=3 in equation (4)
2(3)+3(2)−12=0
6+6−12=0
12−12=0
0=0
Again put x=4,y=0 in equation (4)
2(0)+3(4)−12=0
0+12−12=0
12−12=0
0=0
Plotting (2,3),(4,0) and joining them, we get another straight line.
These lines intersect at the point (2,3) and therefore the solution of the equation is x=2,y=3 .