wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve the equations: xy=1 and 2y+3x=12 using graphical method.

A
(1,2)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
(2,3)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
(3,3)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
(1,2)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B (2,3)
xy=1 ----- (1)

2y+3x=12 ----- (2)

From equation (1) assume the value of x and y to satisfy the equation to zero.

xy+1=0 ------- (3)

Put x=2,y=3 in equation (3)

23+1=0

1+1=0

0=0

Again put x=4,y=5 in equation (3)

45+1=0

1+1=0

0=0

Now plotting (2,3),(4,5) and joining them, we get a straight line.

From equation (2) assume the value of x and y to satisfy the equation to zero.

2y+3x12=0 ----- (4)

Put x=2,y=3 in equation (4)

2(3)+3(2)12=0

6+612=0

1212=0

0=0

Again put x=4,y=0
in equation (4)

2(0)+3(4)12=0

0+1212=0

1212=0

0=0

Plotting (2,3),(4,0) and joining them, we get another straight line.

These lines intersect at the point (2,3) and therefore the solution of the equation is x=2,y=3 .

777482_447145_ans_3d64ff7f51f24880a857f6cec2b93abc.png

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Graphical Solution
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon