Question

Solve the equations $x+y=3$ and $3x-2y=4$ using graph

Answer 1

We draw graphs of the equations $x+y=3$ and $3x-2y=4$. Then locate their point of intersection.
Recall, that it is enough to know two points to draw a straight line. Consider $x+y=3$. Taking $x=0$, we get $y=3$. Taking $y=0$, we get $x=3$. Thus $(0,3)$ and $(3,0)$ are on the straight line $x+y=3$.
Take a graph paper. Fix your coordinate system $x\iff y$ axis on the graph paper. Locate $A=(3,0)$ and $B=(0,3)$ with respect to this coordinate system.
Join $A$ and $B$ and extend it to a straight line.
Consider the equation $3x-2y=4$. If we take $x=0$, we obtain $y=-2$. Similarly, $x=4$ gives $y=4$. Thus $C=(0,-2)$ and $D=(4,4)$ are points on the straight line $3x-2y=4$. Locate these points on the graph paper. Join them and extend to a straight line.
Now we have two straight line. They intersect at a point E. Looking at the graph, you see that $E$ has coordinates $(2,1)$. Thus $x=2$ and $y=1$ is the solution. We may verify it: $2+1=3$ and $3\left(2\right)-2\left(1\right)=6-2=4$.