Question

Solve the following
1)$(4^0+5^{-1})\times 5^2\times \frac{1}{3}$
2)$(2^{-1}+3^{-1}+4^{-1})\times \frac{3}{4}$

Answer 1

(1) Given

$(4^0+5^{-1})\times 5^2\times \frac{1}{3}$

$=(1+\frac{1}{5})\times 25\times \frac{1}{3}$

$=\left(\frac{5+1}{5}\right)\times 25\times \frac{1}{3}$

$=\frac{6}{5}\times 25\times \frac{1}{3}$

$=6\times 5\times \frac{1}{3}$

$=2\times 5$

$=10$

(2) Given

$(2^{-1}+3^{-1}+4^{-1})\times \frac{3}{4}$

$=(\frac{1}{2}+\frac{1}{3}+\frac{1}{4})\times \frac{3}{4}$

$=\left(\frac{6+4+3}{12}\right)\times \frac{3}{4}$

$=\frac{13}{12}\times \frac{3}{4}$

$=\frac{13}{16}$