Solve the following
$- 2 (x + 3) = 5$

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Solution

Given :- $- 2 (x + 3) = 5$
⇒ $- 2 x - 6 = 5$ (Expanding the bracket on L.H.S. )
⇒ $- 2 x = 5 + 6$ (Transporting $6$ to R.H.S.)
⇒ $- 2 x = 11$
⇒ $\frac{- 2 x}{- 2} = \frac{11}{- 2}$ (Dividing both side of equation by $- 2$ )
⇒ $x = \frac{- 11}{2}$
Therefore, $x = \frac{- 11}{2}$ is the required solution

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