Question

Solve the following
$3a+5b=26;a+5b=27$

Answer 1

$3a+5b=26$

$-a-5b=-27$

__________

$2a=-1$ (on subtracting)

$a=\frac{-1}{2}$

$5b=27-a$

$5b=27+\frac{1}{2}=\frac{55}{2}$

$b=\frac{11}{2}$

$\therefore a=\frac{-1}{2},b=\frac{11}{2}$