Question 67
Solve the following:
3x−x−23=4−x−14
Given, 3x−x−23=4−x−14⇒9x−(x−2)3=16−(x−1)4⇒4(9x−x+2)=3(16−x+1)⇒4(8x+2)=3(−x+17)⇒32x+8=−3x+51⇒32x+3x=51−8⇒35x=43⇒35x35=4335∴x=4335