Question 60

Solve the following:

4t-3-(3t+1)=5t-4

Open in App

Solution

Given, 4t-3-(3t+1)=5t-4
$\Rightarrow 4 t - 3 - 3 t - 1 = 5 t - 4 \Rightarrow t - 4 = 5 t - 4 \Rightarrow t - 5 t = - 4 + 4 \Rightarrow - 4 t = 0 \Rightarrow \frac{- 4 t}{- 4} = \frac{0}{- 4} ∴ t = 0$

Suggest Corrections

Similar questions

Question 60

Solve the following:

4t-3-(3t+1)=5t-4

Question 68

Solve the following:

$\frac{3 t + 5}{4} - 1 = \frac{4 t - 3}{5}$

Question 74

Solve the following:

$\frac{3 t - 2}{3} + \frac{2 t + 3}{2} = t + \frac{7}{6}$

When we divide $3 t^{4} + 5 t^{3} - 7 t^{2} + 2 t + 2$ by $t^{2} + 3 t + 1$ , we get $3 t^{2} - 4 t + 2$ as quotient.

Join BYJU'S Learning Program

Explore more

Join BYJU'S Learning Program