Question

Solve the following:

$\frac{5(1–x)+3(1+x)}{1–2x}=8$

Answer 1

Step 1: Apply cross multiplication

$\frac{5(1–x)+3(1+x)}{1–2x}=8$

$$\begin{gathered} 5(1–x)+3(1+x)=8\times (1–2x) \\ \Rightarrow 5–5x+3+3x=8–16x \\ \Rightarrow 8–2x=8–16x \end{gathered}$$

Step 2: Rearrange the terms and combine like terms.

$$\begin{gathered} \Rightarrow 16x–2x=8–8 \\ \Rightarrow 14x=0 \\ \Rightarrow x=\frac{0}{14} \\ \Rightarrow x=0 \end{gathered}$$

The value of $x$is $0.$