Question

Solve the following:

$5\frac{3}{9}+2\frac{1}{9}$

Answer 1

Convert the given fractions into improper fractions, then simplify by taking L.C.M

The improper fraction of $5\frac{3}{9}+2\frac{1}{9}$ is

$$\begin{gathered} 5\frac{3}{9}+2\frac{1}{9} \\ =\frac{5\times 9+3}{9}+\frac{2\times 9+1}{9} \\ =\frac{45+3}{9}+\frac{18+1}{9} \\ =\frac{48}{9}+\frac{19}{9} \end{gathered}$$

Now consider $\frac{48}{9}+\frac{19}{9}$

So,

$$\begin{gathered} \frac{48}{9}+\frac{19}{9} \\ =\frac{48+19}{9} \\ =\frac{67}{9} \end{gathered}$$

Hence, $5\frac{3}{9}+2\frac{1}{9}$ is $\frac{67}{9}$