Question

Solve the following
$8x^3-6x^2+x=0$

Answer 1

Now,

$8x^3-6x^2+x=0$

or, $x(8x^2-6x+1)=0$

or, $x(8x^2-4x-2x+1)=0$

or, $x\left\{4x\right(2x-1)-1(2x-1\left)\right\}=0$

or, $x(4x-1)(2x-1)=0$

or, $x=0,\frac{1}{4},\frac{1}{2}$.