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Quadratic Formula

Solve the fol...

Question

Solve the following.
$a b x^{2} + (b^{2} - a c) x - b c = 0$

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Solution

$a b x^{2} + (b^{2} - a c) x - b c = 0.$
$x = \frac{- B \pm \sqrt{B^{2} - 4 A C}}{2 A}$
$= \frac{- (b^{2} - a c) \pm \sqrt{(b^{2} - a c)^{2} + 4 a b . b c}}{2 \times a b}$
$x = \frac{- (b^{2} - a c) \pm (b^{2} + a c)}{2 a b} = \frac{4 a c}{2 a b} o r \frac{- 2 b^{2}}{2 a b}$
$x = \frac{2 c}{b}, \frac{- 2 b}{a}$

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