Question

Solve the following algebraic expressions by both trial and error method and balancing equation.
$2x=5$

Answer 1

Given $2x=5$

Let $x=1,LHS=2\left(1\right)=2,RHS=5$

As $LHS\ne RHS$

Let $x=\frac{5}{2}$

$LHS=2(\frac{5}{2})=5,RHS=5$

$LHS=RHS$

By trial and error method

So $x=\frac{5}{2}$

By balancing equation

$2x=5⟹x=\frac{5}{2}$