Question

Solve the following algebraic expressions by both trial and error method and balancing equation.
$7x=4$

Answer 1

Given $7x=4$

Let $x=1,LHS=7\left(1\right)=7,RHS=4$

As $LHS\ne RHS$

Let $x=\frac{4}{7}$

$LHS=7(\frac{4}{7})=4,RHS=4$

$LHS=RHS$

By trial and error method

So $x=\frac{4}{7}$

By balancing equation

$7x=4⟹x=\frac{4}{7}$