Question

Solve the following and find the value of $x$:

$\frac{x-2}{4}+\frac{1}{3}=x-\frac{2x-1}{3}$

• A. $-3$
• B. $3$
• C. $-6$
• D. $6$

Answer 1

The correct option is C $-6$

Given, $\frac{x-2}{4}+\frac{1}{3}=x-\frac{2x-1}{3}$

L.C.M. of $4$ and $3$ is $12$.

Therefore, $3(x-2)+4=12x-4(2x-1)$

$\Rightarrow 3x-6+4=12x-8x+4$

$\Rightarrow 3x-2=4x+4$

$\Rightarrow -2-4=4x-3x$

$\Rightarrow x=-6$