Solve the following and write the quotient and remainder:
$(8 p^{3} - 4 p^{2}) \div 2 p^{2}$

Open in App

Solution

$4 p - 2 p$

$2 p^{2}) 8 p^{3} - 4 p^{2}$
$8 p^{3}$

$0 - 4 p^{2}$
$- 4 p^{2}$

$x$
_
Quotient $= 4 p - 2$
Remainder $= 0$ .

Suggest Corrections

Similar questions

(8 p^{3} - 4 p^{2}) \div 2 p^{2}

(5 x^{3} - 3 x x^{2}) \div x^{2}

(8 p^{3} - 4 p^{2}) \div 2 p^{2}

(2 y^{3} + 4 y^{2} + 3) \div 2 y^{2}

(8 p^{3} - 4 p^{2}) \div 2 p^{2}

(8 p^{3} - 4 p^{2}) \div 2 p^{2}

40 m^{5} \div - 30 m^{3}

Join BYJU'S Learning Program