Question

Solve the following, by elimination [2 MARKS]

$2x+y=12$

$x-3y=-8$

Answer 1

Concept : 1 Mark
Calculation : 1 Mark

Given equations are,

$2x+y=12\dots \left(i\right)$

$x-3y=-8\dots \left(ii\right)$

Multiplying Equation (i) by 3, we get,

$6x+3y=36\dots \left(iii\right)$

Adding (ii) & (iii), we get,

$7x=28$

$\Rightarrow x=4$

Sustituting the value of x in equation (ii), we get,

$x-3y=-8$

$4-3y=-8$

$\Rightarrow y=4$

$\therefore x=4,y=4$