Question

Solve the following by using the method of completing square.
$x^2+6x-7=0$

Answer 1

$Thegivenequation:x^2+6x-7=0x^2+\mathrm{2.3.}x-7=0x^2+\mathrm{2.3.}x+3^2-3^2-7=0{\left(x+3\right)}^2-16=0{\left(x+3\right)}^2=16$

$x+3=\pm 4$

$x=1,-7$

Hence, this is the answer.