Solve the following cryptarithm:

$37$
$+ A B - ----- -$
$9 A - -- -$

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Solution

$37 + A B = 9 A$

$n u m b e r s i n t h e t e n s p o s i t i o n a r e m u l t i p l i e d b y 10 w h e n w e b r e a k t h e n u m b e r$
$(30 + 7) + (10 A + B) = 90 + A$
$7 + B = A$

$3 + A = 9$

$I f A = 6, B = - 1, n o t p o s s i b l e$
$7 + B = 10 + A$
$3 + A = 8$
$i . e, A = 5, B = 8$

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Similar questions

\begin{matrix} 3 & 7 \\ + & A & B \end{matrix} \begin{matrix} 9 & A \end{matrix}

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$\begin{matrix} 3 & 7 + A & B 9 & A \end{matrix}$

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