Question

Solve the following.
$\frac{{\left(7p^2{q}^2{r}^6\right)}^2{\left(4pqr\right)}^3}{{\left(14p{q}^{10}{r}^4\right)}^2}$

Answer 1

We have,

$\frac{{\left(7p^2{q}^2{r}^6\right)}^2{\left(4pqr\right)}^3}{{\left(14p{q}^{10}{r}^4\right)}^2}$

$=\frac{(49\times p^4\times q^4\times r^{12})\times (64\times p^3\times q^3\times r^3)}{(196\times p^2\times q^{20}\times r^8)}$

$=\frac{49\times 64\times (p^7\times q^7\times r^{15})}{(196\times p^2\times q^{20}\times r^8)}$

$=\frac{49\times 16\times p^5\times r^7}{49\times q^{13}}$

$=\frac{16\times p^5\times r^7}{q^{13}}$

Hence, this is the answer.