Question

Solve the following
$\frac{x-1}{4}+\frac{x-2}{3}=4\frac{1}{6}$

Answer 1

$\frac{x-1}{4}+\frac{x-2}{3}=4\frac{1}{6}$

$\frac{3(x-1)+4(x-2)}{4}=\frac{25}{6}$

$6(3x-3+4x-8)=25\times 4$

$6(7x-11)=100$

$42x-66=100$

$42x=100+66$

$x=\frac{166}{42}$

$\to x=\frac{83}{21}$

$\to x=3\frac{20}{21}$