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Question

Solve the following differential equation:
dy=(1+x+y+xy) dx

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Solution

Consider the given differential equation

dydx=1+x+y+xy

dydx=(1+x)+y(1+x)

dydx=(1+x)(1+y)

dy(1+y)=(1+x)dx

dy(1+y)=(1+x)dx

logc|1+y|=x+x22+C

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