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Question

Solve the following differential equation: x2dydx=2xy+y2.

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Solution

Given,

x2dydx=2xy+y2

dydx=2yx+y2x2

y=vxdydx=xdvdx+v

xdvdx+v=2v+v2

xdvdx=v+v2

dvv+v2=dxx

log(vv+1)=logx+logc

log(yx+1)=logx+logc

yx+1=cx

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