Solve the following eqautions :
$x + 2 y = 10$
$3 x + 2 y = 20$

x = 5, y = \frac{5}{2}

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x = \frac{5}{2}, y = 5

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x = 5, y = 5

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x = \frac{5}{2}, y = \frac{5}{2}

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Solution

The correct option is A $x = 5, y = \frac{5}{2}$
$x + 2 y = 10$ .....(1)
$3 x + 2 y = 20$ .........(2)
Subtracting equation 1 from 2, we get,
$2 x = 10$
$x = 5$
Putting this value in equation 1, we get,
$y = \frac{5}{2}$

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