Question

Solve the following equation:
$3(n-4)+2(4n-5)=5(n+2)+16$

Answer 1

Given, $3(n-4)+2(4n-5)=5(n+2)+16$

$⟹$ $3n-12+8n-10=5n+10+16$ ...[By Distribution Law]

$⟹$ $11n-22=5n+26$ ...[On simplifying]

$⟹$ $11n-5n=22+26$ ...[Transposing $x$ terms to one side]

$⟹$ $6n=48$

$⟹$ $n=\frac{48}{6}$

$⟹$ $n=8$.