Question

Solve the following equation
$3x-4y=1$;
$-2x+\frac{8}{3}y=5$

Answer 1

The given equations are

$3x-4y=1$ ......(1)

$-2x+\frac{8}{3}=5$ .....(2)

multiply (1) by 2 and (2) by 3

$6x-8y=2$ ....(3)

$-6y+8y=15$ .....(4)

Add equation (3) and (4)

$0=17$ which is not possible Therefore the two equations goes not have any solution.