Solve the following equation
$4 (m + 3) = 18$

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Solution

Given:- $4 (m + 3) = 18$
⇒ $4 m + 12 = 18$ (Expanding the bracket on L.H.S. )
⇒ $4 m = 18 - 12$ (Transporting $12$ to R.H.S.)
⇒ $4 m = 6$
⇒ $\frac{4 m}{4} = \frac{6}{4}$ (Dividing both side of equation by $4$ )
⇒ $m = \frac{3}{2}$
Therefore, $m = \frac{3}{2}$ is the required solution

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\frac{18 - 2 y}{y - 4} = \frac{4}{3}

Question 3(ii)
Solve the following equation by trial and error method:
3m- 14 = 4

\frac{2 x}{3} = 18

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