Question

Solve the following equation and check your results:
$4z+3=6+2z$

Answer 1

Transpose $2z$ to LHS and $3$ to RHS
$4z-2z=6-3$
$2z=3$
$z=\frac{3}{2}$
LHS $\Rightarrow 4z+3=4\times \frac{3}{2}+3=9$
RHS $\Rightarrow 6+2z=6+2\times \frac{3}{2}\Rightarrow 6+3=9$
LHS $=$ RHS
Hence proved