Question

Solve the following equation and check your results:
$5t-3=3t-5$

Answer 1

Given: $5t-3=3t-5$

$\Rightarrow 5t-3t=3-5$

$\Rightarrow 2t=-2$

On dividing both sides by $2$, we get

$t=-1$

checking results by substituting $t$ value in LHS and RHS

$\Rightarrow L.H.S=5t-3$

$=5\times (-1)-3=-8$

$\Rightarrow R.H.S=3t-5$

$=3\times (-1)-5=-8$

$\therefore LHS=RHS$
Hence proved.