Question

Solve the following equation and find the value of $x$

$2^{x+3}=4^{x-1}$

Answer 1

$2^{x+3}=4^{x-1}$

$2^{x+3}=2^{2(x-1)}$

As the bases are equal, equating the powers

$x+3=2(x-1)$

$x+3=2x-2$

$x=5$