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Question

Solve the following equation by reduction method:
x+3y+3z=16
x+4y+4z=21
x+3y+4z=19

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Solution

∣ ∣133161442113419∣ ∣
R2R2R1
=∣ ∣13316010513419∣ ∣
R3R3R1
=∣ ∣1331601050013∣ ∣
z=3,y=5,x+3y+3z=16
x+3×5+3×3=16
x159=16
x=16+24=8
x=8,y=5,z=3


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