Question

Solve the following equation by the trial-and-error method: $y+9=13$

Answer 1

We have $y+9=13$

At $y=0$ LHS$=0+9=9\ne$RHS

At $y=1$ LHS$=1+9=10\ne$RHS

At $y=2$ LHS$=2+9=11\ne$RHS

At $y=3$ LHS$=3+9=12\ne$RHS

At $y=4$ LHS$=4+9=13=$RHS

$\therefore y=4$ is a root of the equation