By trial and error method, we will check different values of a amd try to solve this equation.
let us take a = 1,
1−2=6
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−1 is not equal to 6 so a=1 is not correct
let us take a=2
2−2=6
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0 is not equal to 6 so a= 2 is not correct
let us take a higher value that is a=7,
7−2=5
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so 5 is not equal to 6
so a=5 is not correct
let take a=8
8−2=6
Here we get the answer so a= 8 is correct value.
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