Question

Solve the following equation by using the method of completing the square:
$4x^2+4bx-(a^2-b^2)=0$

Answer 1

$4x^2+4bx-(a^2-b^2)=0$

$4x^2+4bx-a^2+b^2=0$

$(2x{)}^2+2.(2x).b+b^2-a^2=0$

$(2x+b{)}^2-a^2=0$