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Question

Solve the following equation by using the method of completing the square:
4x2+4bx(a2b2)=0

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Solution

4x2+4bx(a2b2)=0

4x2+4bxa2+b2=0

(2x)2+2.(2x).b+b2a2=0

(2x+b)2a2=0


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