Question

Solve the following equation: $\frac{9x}{7-6x}=15$

• A. $x=\frac{25}{72}$
• B. $x=\frac{35}{33}$
• C. $x=\frac{45}{39}$
• D. $x=\frac{22}{45}$

Answer 1

The correct option is B $x=\frac{35}{33}$

Given, $\frac{9x}{7-6x}=15$
$9x=105-90x$

Add $90x$ on both the sides, we get

$9x+90x=105-90x+90x$
$99x=105$
$\therefore x=\frac{105}{99}=\frac{35}{33}$