1
Question
Solve the following equation:
3y+42−6y=−25
3y+42−6y=−25
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Solution
Given equation is 3y+42−6y=−25
On multiplying both sides by 5(2−6y), we get:
5(3y+4)=−2(2−6y)
⇒15y+20 =−4+12y
Transposing 12y to LHS and 20 to RHS, we get:
15y−12y=−4−20
⇒3y=−24
⇒y=−8
Hence, y=−8 is the solution of the given equation.
On multiplying both sides by 5(2−6y), we get:
5(3y+4)=−2(2−6y)
⇒15y+20 =−4+12y
Transposing 12y to LHS and 20 to RHS, we get:
15y−12y=−4−20
⇒3y=−24
⇒y=−8
Hence, y=−8 is the solution of the given equation.
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