Question

Solve the following equation:
$\frac{7y+4}{y+2}=\frac{-4}{3}$

Answer 1

$\frac{7y+4}{y+2}=\frac{-4}{3}$
Multiply $3(y+2)$ to both sides
$3(7y+4)=-4(y+2)$
$21y+12=-4y-8$
$21y+4y=-8-12$
$25y=-20$
$y=\frac{-20}{25}$

$\Rightarrow y=\frac{-4}{5}$