Question

Solve the following equation:
$21+\sqrt{2x-7}=x$

Answer 1

$21+\sqrt{2x-7}=x\sqrt{2x-7}=x-212x-7=x^2-42x+441x^2-44x+448=0x=\frac{44\pm \sqrt{{44}^2-4.448}}{2}=\frac{44\pm 2\sqrt{484-44.8}}{2}=\frac{22\pm \sqrt{36}}{2}=22\pm 6=28,16$