Question

Solve the following equation:
$3^{2x-3}-9^{x-1}+{27}^{\frac{2x}{3}}=675$

Answer 1

$3^{2x-3}-9^{x-1}+{27}^{\frac{2x}{3}}=675$

$3^{2x-3}-3^{2x-2}+3^{2x}=675$

$3^{2x-3}(1-3+27)=675$

$3^{2x-3}.25=675$

$3^{2x-3}=3^3$

$x=3$