Question

Solve the following equation:
$3\sin x=(1-\cos x)$

Answer 1

$3\sin x=1-\cos x$

$6\sin \frac{x}{2}\cos \frac{x}{2}={2\sin }^2\frac{x}{2}$

$⟹\tan \frac{x}{2}=3,\frac{x}{2}=n\pi +{tan}^{-1}\left(3\right),x=2n\pi +{2tan}^{-1}\left(3\right)$

and, $\sin \frac{x}{2}=0,\frac{x}{2}=n\pi ,x=2n\pi .$