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Question

Solve the following equation:
42x5.41x+4=0

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Solution

42x5.41x+4=0
Let 1x=tx0
42t5.4t+4=0
(4t)25.(4t)+4=0
Let 4t=u
u25u+4=0
u24uu+4=0
(u4)(u1)=0
u=4,1
4t=4,1
4t=4 & 4t=1
t=1 & t=0
1x=1,0
x=1


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