Question

Solve the following equation:
$4^x\cdot 5^{x+1}={5.20}^{2-x}$

Answer 1

$4^x{.5}^{x+1}={5.20}^{2-x}$

$2^{2x}{.5}^{x+1}=2^{4-2x}{.5}^{3-x}$

comparing powers in both sides we get

$x+1=3-x⟹x=1$